I hope you take the time to actually read this.

By : David Nash   Dept. Of Chemistry    Univ. of illinois

We seem to have another pupil of the Michael Courtney school of
atmospheric physics. First, clouds and water vapor are far less
dense than liquid water. In the case of water vapor at (say) 25 C
and 1 atmosphere pressure, liquid water is more dense than water
vapor by a factor of 1370. To get enough water to flood the Earth to
6 miles deep (the height of Mt. Everest, plus a little more for good
measure), you'd need a vapor layer roughly 1370x as deep as that 6
miles, or 8200 miles. Fat chance. Actually, this does neglect the
inevitable compression of the stuff, which would show a pressure
gradient like that of the Earth's current atmosphere. Even with this
taken into account, though, you're still talking about at least tens
of miles of water vapor at a density vastly exceeding anything ever
recorded in the Earth's atmosphere. Clouds are denser than water
vapor, since the consist of small droplets of liquid water, but they
are still vastly less dense than the liquid.

Next, there is the problem of air pressure. Those six miles of water
don't magically become less massive by just being vaporized and
suspended in the air.

Next, there is the problem of heat of condensation, when all that
water condenses to rain down. Going back to the Flood Fest of last
fall, the amount of water required to cover the Earth to the depth
of Everst is 4.5E9 km^3. This is 4.5E21 kg, and the energy this
releases on condensing is (2260 kJ/kg) * 4.5E21 kg = 1.02E25 kJ =
1.02E28 J. By contrast, the Earth receives 5.52E24 J per YEAR from
the Sun. Neat trick -- a flood that hits the Earth with as much
energy as it gets from centuries of solar radiation.

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By : Marty Leipzig   A Phd  Geologist

   If, for no other reason to educate some and irritate others, what
   follows is a mathematical treatise on the impossibility of a Biblical
   Great Flood...

   In order to flood the Earth to the Biblical depth of "10 cubits"
   above the highest mountains of the Earth; you would need some 4.427
   billion cubic kilometers of water. The mass of this water would be
   4.427 x 10^21 kilograms. The current amount of water in the Earth's
   hydrosphere is only 1.37 billion cubic kilometers. So, where did the
   other 2 hydrospheres full of water come from? It could not come from
   water vapor (or clouds) because the atmospheric pressure would be 842
   times greater than it is now. Further, the latent heat relaeased when
   the vapor condenses into liquid would be enough to raise the
   temperature of the Earth's atmosphere to 3,570 C (6,458 F).

   Someone once suggested that a "Vapor Canopy" covered the Earth, and
   this is where all that water came from. Not so at all. What would
   keep that water in orbit above the Earth? This niggling little
   property called gravity would cause it to fall. Why should that take
   40 days and 40 nights?  Further, this mass of water (some 4.427 X
   10^21 Kg) stores a tremendous amount of potential energy which would
   be converted to kinetic energy when the water falls and would be
   converted to heat when it strikes the Earth. This potential energy
   (Ep=M*g*H; where M=mass of water, g=gravitational constant and
   H=height of water above the Earth's surface) could be calculated. If
   4.427 x 10^21 is divided by 40 days, it yields 1.107 x 10^20 Kg/day.
   If H=16,000m (approximately 10 miles), the released energy, per day,
   would equal 1.735 x 10^25 joules. The amount of energy the Earth
   would have to radiate per m^2/s is energy divided by surface area of
   the Earth times the number of seconds in one day; thus: Ep=1.735 x
   10^25/(4*3.14159*((6386)^2)*86,400) = 391,935.096 j/m^2/s.

   The Earth currently radiates 215 j/m^2/s at an average temperature of
   280 K. Using the Stephan-Boltzmann fourth power law to calculate
   temperature increase:

   E(increase)/E(normal)=T^4(increase)/T^4(normal); so

   E(normal) = 215
   E(increase) = 391,935.096
   T(normal) = 280  (turn the crank, and...)
  ----------------------
   T(increase) = 1,800 K.

   The temperature of the Earth would have to rise 1,800 degrees.
   Further, the water level would rise an average of 14 cm. per minute
   for 40 days. In 13 minutes, the water level would be over 2 m. in
   depth. Further, water under standard pressure would not exist as a
   liquid at 1,800 K.

   So much for that flood...